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(3^(0.5x+1))^2-3(3^-x)=-6
We move all terms to the left:
(3^(0.5x+1))^2-3(3^-x)-(-6)=0
We add all the numbers together, and all the variables
(3^(0.5x+1))^2-3(3^-x)+6=0
We multiply parentheses
(3^(0.5x+1))^2+3x+6-=0
We add all the numbers together, and all the variables
3x+(3^(0.5x+1))^2=0
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